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(1/5)^x-7=25^3x
We move all terms to the left:
(1/5)^x-7-(25^3x)=0
Domain of the equation: 5)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/5)^x-25^3x-7=0
We multiply all the terms by the denominator
(+1-25^3x*5)^x-7*5)^x=0
Wy multiply elements
(+1-25^3x*5)^x-35x=0
We add all the numbers together, and all the variables
-35x+(+1-25^3x*5)^x=0
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